RD Sharma Solutions Class 9 Maths Chapter 2 – Free PDF Download
RD Sharma Solutions for Class 9 Maths Chapter 2 – Exponents of Real Numbers help students to understand concepts like integral exponents of a real number, laws of exponents and rational powers. To facilitate easy learning and help students understand the concepts of exponents of Real Numbers, free RD Sharma Solutions are provided here, which can be further downloaded in the form of a PDF. Practising textbook questions following the RD Sharma Solutions for Class 9 Maths Chapter 2 improves conceptual knowledge among students. Those who aim to secure high marks are suggested to download solutions in PDF format from the link given below.
BYJU’S RD Sharma Solutions Class 9 Maths Chapter 2 provides a clear explanation of each concept in a simple and understandable language. These solutions have been designed keeping in mind the student’s grasping skills to solve the CBSE Class 9 Maths problems with ease. If a is a positive real number and n is a positive integer, then the principal nth root of a is the unique positive real number x such that xn = a. The principal nth root of a is denoted by a(1/n).
Chapter 2 Exponents Of Real Numbers
- Rd Sharma Class 9 Solutions Maths Chapter 1 Number System
- Rd Sharma Class 9 Solutions Maths Chapter 2 Exponents of Real Numbers
- Rd Sharma Class 9 Solutions Maths Chapter 3 Rationalisation
- Rd Sharma Class 9 Solutions Maths Chapter 4 Algebraic Identities
- Rd Sharma Class 9 Solutions Maths Chapter 5 Factorization of Algebraic Expressions
- Rd Sharma Class 9 Solutions Maths Chapter 6 Factorization of Polynomials
- Rd Sharma Class 9 Solutions Maths Chapter 7 Introduction To Euclids Geometry
- Rd Sharma Class 9 Solutions Maths Chapter 8 Lines and Angles
- Rd Sharma Class 9 Solutions Maths Chapter 9 Triangle and Its Angles
- Rd Sharma Class 9 Solutions Maths Chapter 10 Congruent Triangles
- Rd Sharma Class 9 Solutions Maths Chapter 11 Coordinate Geometry
- Rd Sharma Class 9 Solutions Maths Chapter 12 Herons Formula
- Rd Sharma Class 9 Solutions Maths Chapter 13 Linear Equation in Two Variables
- Rd Sharma Class 9 Solutions Maths Chapter 14 Quadrilaterals
- Rd Sharma Class 9 Solutions Maths Chapter 15 Areas of Parallelograms and Triangles
- Rd Sharma Class 9 Solutions Maths Chapter 16 Circles
- Rd Sharma Class 9 Solutions Maths Chapter 17 Constructions
- Rd Sharma Class 9 Solutions Maths Chapter 18 Surface Area and Volume of a Cuboid and Cube
- Rd Sharma Class 9 Solutions Maths Chapter 19 Surface Area and Volume of Right Circular Cylinder
- Rd Sharma Class 9 Solutions Maths Chapter 20 Surface Area and Volume of Right Circular Cone
- Rd Sharma Class 9 Solutions Maths Chapter 21 Surface Area and Volume of Sphere
- Rd Sharma Class 9 Solutions Maths Chapter 22 Tabular Representation of Statistical Data
- Rd Sharma Class 9 Solutions Maths Chapter 23 Graphical Representation of Statistical Data
- Rd Sharma Class 9 Solutions Maths Chapter 24 Measures of Central Tendency
- Rd Sharma Class 9 Solutions Maths Chapter 25 Probability
- Exercise 2.1 Chapter 2 Exponents of Real Numbers
- Exercise 2.2 Chapter 2 Exponents of Real Numbers
- VSAQs Chapter 2 Exponents of Real Numbers
RD Sharma Solutions for Class 9 Maths Chapter 2 Exponents of Real Numbers
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Exercise 2.1
Question 1: Simplify the following
(i) 3(a4 b3)10 x 5 (a2 b2)3
(ii) (2x -2 y3)3
Solution:
Using laws: (am)n = amn , a0 = 1, a-m = 1/a and am x an = am+n]
(i) 3(a4 b3)10 x 5 (a2 b2)3
On simplifying the given equation, we get;
= 3(a40 b30) x 5 (a6 b6)
= 15 (a46 b36)
[using laws: (am)n = amn and am x an = am+n](ii) (2x -2 y3)3
On simplifying the given equation, we get;
= (23 x -2 × 3 y3×3)
= 8 x -6 y9
(iii)
Question 2: If a = 3 and b =-2, find the values of:
(i) aa+ bb
(ii) ab + ba
(iii) (a+b)ab
Solution:
(i) aa+ bb
Now putting the values of ‘a’ and ‘b’, we get;
= 33 + (−2)−2
= 33 + (−1/2)2
= 27 + 1/4
= 109/4
(ii) ab + ba
Now putting the values of ‘a’ and ‘b’, we get;
= 3−2 + (−2)3
= (1/3)2 + (−2)3
= 1/9 – 8
= −71/9
(iii) (a+b)ab
Now putting the values of ‘a’ and ‘b’, we get;
= (3 + (−2))3(−2)
= (3–2))−6
= 1−6
= 1
Question 3: Prove that
Solution:
(i) L.H.S. =
= R.H.S.
(ii) We have to prove here;
L.H.S. =
=R.H.S.
(iii) L.H.S. =
= R.H.S.
Question 4: Prove that
Solution:
(i) L.H.S
= R.H.S.
(ii) L.H.S
= R.H.S.
Question 5: Prove that
Solution:
(i) L.H.S.
= R.H.S.
(ii)
L.H.S.
= R.H.S.
Question 6: If abc = 1, show that
Solution:
Exercise 2.2
Question 1: Assuming that x, y, z are positive real numbers, simplify each of the following:
Solution:
Question 2: Simplify
Solution:
Question 3: Prove that
Solution:
(i) L.H.S.
=R.H.S.
Question 4.
Show that:
Solution:
Exercise-VSAQs
Question 1: Write (625)–1/4 in decimal form.
Solution:
(625)–1/4 = (54)-1/4 = 5-1 = 1/5 = 0.2
Question 2: State the product law of exponents:
Solution:
To multiply two parts having same base, add the exponents.
Mathematically: xm x xn = xm +n
Question 3: State the quotient law of exponents.
Solution:
To divide two exponents with the same base, subtract the powers.
Mathematically: xm ÷ xn = xm – n
Question 4: State the power law of exponents.
Solution:
Power law of exponents :
(xm)n = xm x n = xmn
Question 5: For any positive real number x, find the value of
Solution:
Question 6: Write the value of {5(81/3 + 271/3 ) 3}1/4 .
Solution:
{5(81/3 + 271/3 ) 3}1/4
= {5(23×1/3 + 33×1/3 ) 3}1/4
= { 5(2 + 3)^3}1/4
= (54 ) 1/4
= 5
RD Sharma Solutions for Class 9 Maths Chapter 2 Exponents of Real Numbers
In the 2nd chapter of Class 9 RD Sharma Solutions students will study important concepts on Exponents of Real Numbers, as listed below:
- Introduction to Exponents of Real Numbers
- Integral exponents of a Real Number
- Laws of Integral Exponents
- Rational Exponents of Real Number
- nth root of a positive Real Number
- Laws of Rational Exponents
To know these concepts present in the RD Sharma textbook in detail, visit BYJU’S website. We also provide CBSE sample papers, previous year question papers and CBSE notes. This will help you in scoring well in your upcoming boards.
Frequently Asked Questions on RD Sharma Solutions for Class 9 Maths Chapter 2
Q1
Why should we download RD Sharma Solutions for Class 9 Maths Chapter 2?
The presentation of each solution in Chapter 2 of RD Sharma Solutions for Class 9 Maths is described in a unique way by the BYJU’S experts. The solutions are explained in a simple and understandable language to improve grasping abilities among students. In order to score good marks, practising RD Sharma Solutions for Class 9 Maths can help to a large extent. This chapter can be used as a model of reference by the students to improve their conceptual knowledge and understand the different ways used to solve the problems with ease.
Q2
Does BYJU’S website provide answers to RD Sharma Solutions for Class 9 Maths Chapter 2 in a detailed way?
Yes, BYJU’S website provides answers to RD Sharma Solutions for Class 9 Maths Chapter 2 in a step-by-step way. This allows the students to learn all the concepts in detail, and clear their doubts as well. Regular practising of these solutions boosts confidence in solving the complex problems in an efficient manner. This also helps them to obtain excellent marks in the board exams.
Q3
Give an overview of concepts present in RD Sharma Solutions for Class 9 Maths Chapter 2.
RD Sharma Solutions for Class 9 Maths Chapter 2 has 2 exercises. The concepts of this chapter are listed below.
1. Introduction to Exponents of Real Numbers
2. Integral exponents of a Real Number
3. Laws of Integral Exponents
4. Rational Exponents of Real Number
5. nth root of a positive Real Number
6. Laws of Rational Exponents